1 Answer
The transformer ratio, also known as the **turns ratio**, is calculated by comparing the number of turns on the primary winding (input side) to the number of turns on the secondary winding (output side). The basic formula to calculate the transformer ratio is:
\[
\text{Transformer Ratio (n)} = \frac{N_p}{N_s}
\]
Where:
- \( N_p \) is the number of turns on the primary winding.
- \( N_s \) is the number of turns on the secondary winding.
### How it works:
1. **Voltage Ratio**: The transformer ratio also relates to the voltage ratio, since the voltage on the primary and secondary windings is proportional to the number of turns:
\[
\frac{V_p}{V_s} = \frac{N_p}{N_s}
\]
Where:
- \( V_p \) is the voltage on the primary winding.
- \( V_s \) is the voltage on the secondary winding.
2. **Current Ratio**: The current on the primary and secondary windings are inversely proportional to the number of turns:
\[
\frac{I_p}{I_s} = \frac{N_s}{N_p}
\]
Where:
- \( I_p \) is the current on the primary winding.
- \( I_s \) is the current on the secondary winding.
### Example:
If a transformer has 1000 turns on the primary and 250 turns on the secondary:
\[
\text{Transformer Ratio} = \frac{1000}{250} = 4
\]
This means the transformer is designed to step down the voltage by a factor of 4. If the primary voltage is 400V, the secondary voltage will be:
\[
V_s = \frac{V_p}{4} = \frac{400V}{4} = 100V
\]
I hope that helps! Let me know if you have more questions or need clarification on anything.
\[
\text{Transformer Ratio (n)} = \frac{N_p}{N_s}
\]
Where:
- \( N_p \) is the number of turns on the primary winding.
- \( N_s \) is the number of turns on the secondary winding.
### How it works:
1. **Voltage Ratio**: The transformer ratio also relates to the voltage ratio, since the voltage on the primary and secondary windings is proportional to the number of turns:
\[
\frac{V_p}{V_s} = \frac{N_p}{N_s}
\]
Where:
- \( V_p \) is the voltage on the primary winding.
- \( V_s \) is the voltage on the secondary winding.
2. **Current Ratio**: The current on the primary and secondary windings are inversely proportional to the number of turns:
\[
\frac{I_p}{I_s} = \frac{N_s}{N_p}
\]
Where:
- \( I_p \) is the current on the primary winding.
- \( I_s \) is the current on the secondary winding.
### Example:
If a transformer has 1000 turns on the primary and 250 turns on the secondary:
\[
\text{Transformer Ratio} = \frac{1000}{250} = 4
\]
This means the transformer is designed to step down the voltage by a factor of 4. If the primary voltage is 400V, the secondary voltage will be:
\[
V_s = \frac{V_p}{4} = \frac{400V}{4} = 100V
\]
I hope that helps! Let me know if you have more questions or need clarification on anything.