To determine **how many 88-ohm resistors are connected in parallel**, we need **more information**, such as:
* The **total equivalent resistance** of the parallel combination
* Or the **total current and voltage**, which could help derive the equivalent resistance using Ohm's law
But since your question is open-ended ("how many resistors..."), I'll explain how to calculate it **step by step** assuming that we are given the **equivalent resistance** of the combination.
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### Basic Formula for Resistors in Parallel
When resistors of the **same resistance value** are connected in parallel, the equivalent resistance $R_{eq}$ is calculated using the formula:
$$
\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots + \frac{1}{R_n}
$$
For **n resistors** of equal value $R$, this becomes:
$$
\frac{1}{R_{eq}} = \frac{n}{R}
\quad \text{or} \quad
R_{eq} = \frac{R}{n}
$$
So, if you know the equivalent resistance and you know each resistor has 88 ohms, you can rearrange the formula to find $n$:
$$
n = \frac{R}{R_{eq}} = \frac{88}{R_{eq}}
$$
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### β
Example:
Letβs say the total equivalent resistance of the parallel network is **11 ohms**.
$$
n = \frac{88}{11} = 8
$$
So, **8 resistors** of 88 ohms each are connected in parallel.
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### Summary
* You **need the equivalent resistance** to find how many resistors are connected in parallel.
* Use the formula $n = \frac{88}{R_{eq}}$
* The more resistors you connect in parallel, the **lower** the equivalent resistance becomes.
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Would you like to provide the equivalent resistance so we can calculate the exact number?