🔍
How to calculate 3 phase kW?

2 Answers

 
Best answer
Calculating the power (in kilowatts, kW) in a three-phase electrical system involves understanding the relationship between voltage, current, and power factor. The formula for calculating three-phase power can vary slightly depending on whether the system is configured as wye (Y) or delta (Δ), but the fundamental concepts remain the same.

### Basic Formula for Three-Phase Power

The general formula for calculating three-phase power is:

\[
P = \sqrt{3} \times V_L \times I_L \times \text{PF}
\]

Where:
- \( P \) = Power in watts (W)
- \( V_L \) = Line voltage (volts)
- \( I_L \) = Line current (amperes)
- \( \text{PF} \) = Power factor (dimensionless, between 0 and 1)

To convert watts to kilowatts, simply divide by 1000:

\[
P_{kW} = \frac{P}{1000} = \frac{\sqrt{3} \times V_L \times I_L \times \text{PF}}{1000}
\]

### Step-by-Step Calculation

1. **Identify Line Voltage (V_L):** This is the voltage between any two phases in the system.

2. **Identify Line Current (I_L):** This is the current flowing through each of the lines.

3. **Determine Power Factor (PF):** This represents the phase difference between the voltage and the current. It is often provided by the equipment manufacturer or can be measured.

4. **Plug Values into the Formula:** Use the values obtained to calculate the total power.

### Example Calculation

Suppose you have a three-phase system with the following specifications:
- Line Voltage \( V_L = 400 \) V
- Line Current \( I_L = 10 \) A
- Power Factor \( \text{PF} = 0.8 \)

1. **Calculate the Power:**

   \[
   P = \sqrt{3} \times 400 \times 10 \times 0.8
   \]
   \[
   P = 1.732 \times 400 \times 10 \times 0.8
   \]
   \[
   P = 1.732 \times 3200
   \]
   \[
   P = 5531.2 \text{ W}
   \]

2. **Convert to kW:**

   \[
   P_{kW} = \frac{5531.2}{1000} = 5.5312 \text{ kW}
   \]

### Notes

- If the system is balanced (meaning the load is the same on all three phases), the above calculations apply directly.
- In unbalanced systems, it may be necessary to calculate the power for each phase separately and sum them to get the total power.

### Conclusion

This calculation is crucial for determining the electrical load and ensuring that systems are operating within their designed capacities. Proper knowledge of line voltage, current, and power factor is essential for accurate calculations.
0 like 0 dislike
To calculate the power in kilowatts (kW) for a three-phase system, you can use the following formula:

\[ \text{Power (kW)} = \frac{\sqrt{3} \times \text{Voltage (V)} \times \text{Current (I)} \times \text{Power Factor (PF)}}{1000} \]

Here's a step-by-step guide:

1. **Determine the Line Voltage (V):** This is the voltage measured between any two of the three-phase lines. For example, in a 415V system, the line voltage is 415V.

2. **Measure the Line Current (I):** This is the current flowing through each of the three phases. Ensure you're using the current measured in amperes (A).

3. **Find the Power Factor (PF):** The power factor is a decimal representing the efficiency of the electrical system, usually between 0 and 1. It accounts for the phase difference between voltage and current. For resistive loads, the power factor is 1, but for inductive or capacitive loads, it will be less than 1.

4. **Apply the Formula:** Plug the values into the formula.

   For example, if you have:
   - Line Voltage (V) = 400V
   - Line Current (I) = 10A
   - Power Factor (PF) = 0.8

   Then:

   \[
   \text{Power (kW)} = \frac{\sqrt{3} \times 400 \times 10 \times 0.8}{1000}
   \]

   \[
   \text{Power (kW)} = \frac{1.732 \times 400 \times 10 \times 0.8}{1000}
   \]

   \[
   \text{Power (kW)} = \frac{554.24}{1000}
   \]

   \[
   \text{Power (kW)} = 0.554 \text{ kW}
   \]

5. **Convert to Kilowatts:** The final result from the formula is in kilowatts.

This formula assumes that the system is balanced and that the loads are evenly distributed across the three phases. If you have an unbalanced load, you'll need to calculate the power for each phase separately and then sum them up.
0 like 0 dislike

Related questions

A 3 phase line of 4 km length delivers 4000 kW at a p.f of 0.8 lagging to a load the resistance and reactance per km of each conductor are 0.2 Ω and 0.5 Ω respectively if the voltage at the supply end is maintained at 11 kV. Calculate the received end voltage and efficiency of line.
Answer : To calculate the **received end voltage** and the **efficiency** of the transmission line, we need to follow these steps: ### 1. **Given data:** - Load power (\( P_L \)) = 4000 kW = 4000 10³ W - Power factor ... approx 10.02 \, \text{kV} \) - **Efficiency of the line**: \( \eta \approx 99.76\% \)...

Show More

The power input to a 500V 50Hz 6Pole 3 phase induction motor running at 975 rpm is 40 kW. The stator losses are 1kW and friction and windage losses are 2kW. Calculate: (i) Slip (ii) Rotor copper loss (iii) Shaft power (iv) Efficiency
Answer : To solve this problem, we can break it down step by step. ### Given Data: - **Voltage (V)**: 500 V - **Frequency (f)**: 50 Hz - **Poles (P)**: 6 - **Speed (N)**: 975 RPM - **Input Power (P_in)**: 40 kW ... { kW}\) 3. **Shaft Power (P_shaft)**: \(37 \text{ kW}\) 4. **Efficiency (η)**: \(92.5\%\)...

Show More

A 3-phase, 500 volt motor load has a power factor of 0.4. Two wattmeter connected to measure the input. They show the input to be 30 KW. Find the reading of each wattmeter?
Answer : To determine the readings of the two wattmeters connected to a 3-phase motor load, we will use the two-wattmeter method, which is commonly used to measure power in 3-phase systems. Here's how the solution can ... \)) reads **9 kW**. Thus, the two wattmeter readings are 21 kW and 9 kW respectively....

Show More

The power input to a six pole, 3 phase, 50 Hz induction motor is 42 kW, the speed being 970 rpm. The stator losses are 1.2 kW and friction and windage losses are 1.8 kW. Find i) slip, ii) Rotor Output iii) Rotor copper loss and iv) Efficiency.
Answer : To solve this problem involving a three-phase induction motor, we can follow these steps: ### Given Data: - Power input, \( P_{in} = 42 \, \text{kW} \) - Stator losses, \( P_{ ... .86\% \) These calculations provide a comprehensive understanding of the motor's performance based on the given data....

Show More

How to calculate 3-phase current?
Answer : Calculating the current in a three-phase system depends on the type of load (balanced or unbalanced) and whether the system is connected in a star (Y) or delta (Δ) configuration. Below, I ... like electrical design and analysis. If you have specific scenarios or further questions, feel free to ask!...

Show More
Welcome to Electrical Engineering, where you can ask questions and receive answers from other members of the community.