The decrease in the electric field inside a dielectric material compared to a vacuum or air can be explained by understanding how dielectrics interact with electric fields. Here’s a detailed breakdown of why this happens:
### 1. **Introduction to Dielectrics**
A dielectric is an insulating material that, when placed in an electric field, becomes polarized. This means that the positive and negative charges within the dielectric align themselves in response to the external electric field.
### 2. **Polarization of Dielectrics**
When a dielectric material is exposed to an electric field, the electric charges within the material shift slightly. This shift creates tiny dipoles (pairs of positive and negative charges) that align with the applied field. The process of this alignment is called polarization.
### 3. **Formation of Bound Charges**
The polarization of the dielectric creates what are known as bound charges on the surfaces of the material. These bound charges effectively set up their own electric field, which opposes the external field applied to the dielectric.
### 4. **Resultant Electric Field**
The total electric field inside the dielectric is the result of the external field and the field created by the bound charges. Mathematically, the electric field \( \mathbf{E}_{\text{inside}} \) inside a dielectric is given by:
\[ \mathbf{E}_{\text{inside}} = \frac{\mathbf{E}_{\text{external}}}{\kappa} \]
where \( \kappa \) (or \( \varepsilon_r \)) is the dielectric constant of the material.
- **Dielectric Constant (\( \kappa \))**: This is a measure of how much the material reduces the electric field inside it compared to a vacuum. For a dielectric material, \( \kappa \) is always greater than 1.
### 5. **Physical Explanation**
Here’s a step-by-step physical explanation:
1. **External Electric Field Application**: When an external electric field is applied to a dielectric, it influences the charges within the dielectric material.
2. **Polarization**: The charges in the dielectric are displaced slightly from their equilibrium positions, creating dipoles. These dipoles align with the applied field.
3. **Opposing Field**: The aligned dipoles create an internal electric field that opposes the external electric field.
4. **Reduction of Field**: The combined effect of the external field and the opposing field from the dipoles results in a reduction of the total electric field inside the dielectric material.
### 6. **Mathematical Interpretation**
To quantify this, consider the relationship between the electric field \( \mathbf{E} \) and the polarization \( \mathbf{P} \). The bound charge density \( \rho_b \) due to polarization is given by:
\[ \rho_b = -\nabla \cdot \mathbf{P} \]
The electric displacement field \( \mathbf{D} \) is related to the electric field \( \mathbf{E} \) and the polarization \( \mathbf{P} \) by:
\[ \mathbf{D} = \epsilon_0 \mathbf{E} + \mathbf{P} \]
In a dielectric material, the relationship is also given by:
\[ \mathbf{D} = \varepsilon \mathbf{E} \]
where \( \varepsilon = \varepsilon_0 \kappa \) is the permittivity of the dielectric material. Hence:
\[ \mathbf{E} = \frac{\mathbf{D}}{\varepsilon} = \frac{\mathbf{D}}{\varepsilon_0 \kappa} \]
Since \( \mathbf{D} \) is the same as in a vacuum, the electric field \( \mathbf{E} \) inside the dielectric is reduced by the factor of the dielectric constant \( \kappa \).
### 7. **Physical Implications**
The decrease in the electric field inside a dielectric has practical implications. For example, in capacitors, inserting a dielectric increases the capacitance because the electric field between the plates is reduced, allowing more charge to be stored for a given voltage.
In summary, the electric field inside a dielectric decreases because the material's polarization creates an opposing electric field, which reduces the overall electric field within the material. This effect is quantified by the dielectric constant of the material, which is always greater than 1, indicating a reduction in the electric field compared to what it would be in a vacuum.