What is the current formula?
2 Answers
The term "current formula" could refer to several things depending on the context. Here are a few possibilities:
1. **Ohm’s Law:**
In electrical engineering, the current \(I\) through a resistor \(R\) with a voltage \(V\) across it is given by Ohm’s Law:
\[
I = \frac{V}{R}
\]
This formula states that current is equal to the voltage divided by the resistance.
2. **Current in an AC Circuit:**
For an alternating current (AC) circuit with a sinusoidal voltage \(V(t) = V_{\text{peak}} \sin(\omega t)\), where \(V_{\text{peak}}\) is the peak voltage and \(\omega\) is the angular frequency, the current \(I(t)\) through a resistor \(R\) is:
\[
I(t) = \frac{V_{\text{peak}}}{R} \sin(\omega t)
\]
3. **Current in a Capacitor:**
For a capacitor with capacitance \(C\) and a time-varying voltage \(V(t)\), the current \(I(t)\) is given by:
\[
I(t) = C \frac{dV(t)}{dt}
\]
This represents the relationship between the changing voltage and the resulting current through the capacitor.
4. **Current in an Inductor:**
For an inductor with inductance \(L\), the voltage \(V(t)\) across it and the current \(I(t)\) through it are related by:
\[
V(t) = L \frac{dI(t)}{dt}
\]
This formula indicates that the voltage across an inductor is proportional to the rate of change of current through it.
If you have a specific context or application in mind, please let me know so I can provide a more tailored explanation!
1. **Ohm’s Law:**
In electrical engineering, the current \(I\) through a resistor \(R\) with a voltage \(V\) across it is given by Ohm’s Law:
\[
I = \frac{V}{R}
\]
This formula states that current is equal to the voltage divided by the resistance.
2. **Current in an AC Circuit:**
For an alternating current (AC) circuit with a sinusoidal voltage \(V(t) = V_{\text{peak}} \sin(\omega t)\), where \(V_{\text{peak}}\) is the peak voltage and \(\omega\) is the angular frequency, the current \(I(t)\) through a resistor \(R\) is:
\[
I(t) = \frac{V_{\text{peak}}}{R} \sin(\omega t)
\]
3. **Current in a Capacitor:**
For a capacitor with capacitance \(C\) and a time-varying voltage \(V(t)\), the current \(I(t)\) is given by:
\[
I(t) = C \frac{dV(t)}{dt}
\]
This represents the relationship between the changing voltage and the resulting current through the capacitor.
4. **Current in an Inductor:**
For an inductor with inductance \(L\), the voltage \(V(t)\) across it and the current \(I(t)\) through it are related by:
\[
V(t) = L \frac{dI(t)}{dt}
\]
This formula indicates that the voltage across an inductor is proportional to the rate of change of current through it.
If you have a specific context or application in mind, please let me know so I can provide a more tailored explanation!