To determine the ratio of the Current Transformers (CTs) on the High Voltage (HV) side of a Three-Phase, 66/11 kV, Star-Delta connected transformer protected by the Merz-Price system, we need to understand how the CT ratios on both sides of the transformer relate to each other.
### Background
The Merz-Price system is a type of differential protection used for transformers. For this system to work correctly, the CT ratios on the High Voltage (HV) side and the Low Voltage (LV) side must be coordinated. In general, the CT ratio on the HV side is selected so that the currents measured by the CTs on both sides of the transformer are comparable, considering the transformer’s turns ratio.
### Given Data
- Transformer ratings: 66 kV (HV) / 11 kV (LV)
- LV CT ratio: 400/5
### Steps to Find the HV CT Ratio
1. **Determine the Transformer Turns Ratio:**
The turns ratio of the transformer can be calculated using the rated voltages of the HV and LV sides. The turns ratio is given by:
\[
\text{Turns Ratio} = \frac{\text{HV Voltage}}{\text{LV Voltage}} = \frac{66\, \text{kV}}{11\, \text{kV}} = 6
\]
2. **Relate the CT Ratios:**
In a transformer protected by the Merz-Price system, the ratio of the CTs on the HV side to those on the LV side should be the same as the turns ratio of the transformer. This ensures that the differential protection operates correctly. Therefore, the CT ratio on the HV side (\( \text{HV CT Ratio} \)) can be found by multiplying the LV CT ratio by the turns ratio of the transformer:
\[
\text{HV CT Ratio} = \text{LV CT Ratio} \times \text{Turns Ratio}
\]
The given LV CT ratio is 400/5. We need to find the ratio on the HV side:
\[
\text{HV CT Ratio} = \left(\frac{400}{5}\right) \times 6
\]
Simplify the calculation:
\[
\text{HV CT Ratio} = 80 \times 6 = 480
\]
Therefore, the HV CT ratio should be 480/5.
### Summary
The ratio of the Current Transformers on the High Voltage (HV) side should be 480/5 to ensure proper differential protection coordination with the given LV CT ratio and the transformer’s turns ratio.