Yes, the resistance of a wire changes when it is cut. To understand why, let's break down the concept of resistance and how it relates to the physical properties of a wire:
### What is Resistance?
Resistance (denoted as **R**) is a measure of how much a material opposes the flow of electric current. It depends on three main factors:
1. **Resistivity (ρ)**: This is a material-specific property that indicates how much the material resists the current. For example, copper has low resistivity, while rubber has high resistivity.
2. **Length (L)**: The longer the wire, the greater its resistance because electrons have to travel further, facing more obstacles.
3. **Cross-sectional Area (A)**: The thicker the wire (i.e., the larger its cross-sectional area), the lower the resistance. A larger area allows more pathways for the current to flow.
The formula for resistance is given by:
\[
R = \frac{\rho L}{A}
\]
- **R** is the resistance,
- **ρ** is the resistivity,
- **L** is the length of the wire,
- **A** is the cross-sectional area.
### Effect of Cutting a Wire
When a wire is cut, one of the key factors—its length (**L**)—changes, which directly affects the resistance.
#### Case 1: Cutting the Wire in Half
If you cut a wire exactly in half, the new length of each piece will be half of the original length. Let's see what happens to the resistance:
- Original resistance of the wire is \( R \).
- After cutting, the length becomes \( \frac{L}{2} \), and assuming the resistivity (**ρ**) and cross-sectional area (**A**) remain unchanged, the resistance of each new piece will be:
\[
R_{\text{new}} = \frac{\rho \times \frac{L}{2}}{A} = \frac{R}{2}
\]
So, after cutting the wire in half, the resistance of each piece will be **half** of the original resistance.
#### Case 2: Cutting the Wire into Unequal Lengths
If the wire is cut into two unequal lengths, the resistance of each piece will depend on the length of each section. A longer piece will have higher resistance, while a shorter piece will have lower resistance. For example, if the wire is cut into a 70% and 30% split:
- The longer piece (70% of original length) will have more resistance because \( R \) increases with length.
- The shorter piece (30% of original length) will have less resistance.
Each piece's resistance can be calculated using the formula \( R = \frac{\rho L}{A} \), using the respective lengths.
#### Case 3: Connecting the Pieces in Series or Parallel
After cutting the wire, you can either use the pieces separately or reconnect them in series or parallel.
- **Series Connection**: If you connect the pieces in series (end-to-end), the total resistance will be the sum of the individual resistances of each piece. In the case of two equal pieces, the total resistance will be:
\[
R_{\text{total}} = R_{\text{half}} + R_{\text{half}} = R
\]
So, the total resistance is the same as the original wire before it was cut.
- **Parallel Connection**: If the pieces are connected in parallel (side-by-side), the total resistance will decrease. For two equal pieces connected in parallel, the total resistance is given by:
\[
\frac{1}{R_{\text{total}}} = \frac{1}{R_{\text{half}}} + \frac{1}{R_{\text{half}}}
\]
\[
R_{\text{total}} = \frac{R_{\text{half}}}{2} = \frac{R}{4}
\]
In this case, the total resistance of the two parallel pieces is **one-fourth** the original resistance of the full wire.
### Summary:
- Cutting a wire reduces its length, and since resistance depends on length, each shorter section of wire will have **less resistance** than the original wire.
- For equal cuts, each piece has half the original resistance.
- The total resistance can change depending on whether you use the pieces separately or reconnect them in series or parallel.
In general, cutting a wire **changes** its resistance because you are altering one of the main factors—**length**—that determines the wire's overall resistance.