The resistance of an insulator generally **decreases** with an increase in temperature. Here's why:
### Explanation:
- **Insulators** are materials that resist the flow of electrical current due to the lack of free electrons or charge carriers. In these materials, electrons are tightly bound to their atoms, and thus, under normal conditions, they do not contribute to electrical conduction.
- As the **temperature increases**, the thermal energy provided to the material excites the atoms and their electrons. This thermal agitation can liberate a small number of electrons, increasing the number of charge carriers slightly. As a result, the material's resistance decreases because more charge carriers are available to participate in conduction, even though the overall conductivity of the insulator remains very low compared to conductors.
- In **semiconductors**, this effect is more pronounced, but even for insulators, there is still a small change in resistance.
### Formula Involved:
For insulators, the temperature dependence of resistance \( R \) can be approximated using an exponential relation:
\[
R(T) = R_0 e^{\frac{E_g}{2kT}}
\]
Where:
- \( R_0 \) is the resistance at a reference temperature.
- \( E_g \) is the energy gap of the material (a property of insulators and semiconductors).
- \( k \) is Boltzmann’s constant.
- \( T \) is the absolute temperature (in Kelvin).
This equation shows that as temperature increases, the exponent becomes smaller, thus reducing the resistance.
### Practical Example:
For materials like **glass** or **ceramic**, which are common insulators, you'll notice that at higher temperatures, their resistance can reduce, but they still do not become conductors. This characteristic is important in designing insulators for high-temperature applications, like in electrical power systems.