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What happens to temperature as you increase resistance?

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Best answer
As resistance increases in a circuit, the temperature typically rises due to the heat generated by the current flowing through the resistive material. This phenomenon is known as Joule heating, where power loss (in watts) is given by the formula \( P = I^2 R \), where \( I \) is the current and \( R \) is the resistance.

If the current remains constant and resistance increases, the power dissipated as heat increases, leading to a rise in temperature. Conversely, if the voltage is constant and resistance increases, the current decreases, which may reduce the heating effect, but the temperature can still rise depending on other factors, such as ambient conditions and heat dissipation methods.

So, in general, increasing resistance can lead to an increase in temperature, especially if current remains significant.
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When you increase the **resistance** in an electrical circuit, the effect on temperature depends on how the other factors in the circuit, such as voltage and current, change. To fully understand this, we must consider two key relationships: **Ohm's Law** and **Joule's Law** (or the power dissipation formula).

### 1. **Ohm’s Law**:
Ohm's Law defines the relationship between voltage (V), current (I), and resistance (R):

\[
V = I \times R
\]

This law shows that for a fixed voltage, if resistance increases, the current decreases, and vice versa.

### 2. **Power Dissipation (Joule’s Law)**:
Joule’s Law relates the electrical power (P) dissipated in a resistor to the current and resistance:

\[
P = I^2 \times R
\]

Power is the rate at which energy is converted to heat, which means power dissipation in a resistor manifests as **heat**, increasing the temperature of the resistor or surrounding environment.

### Three Scenarios for Increasing Resistance:

#### **Scenario 1: Constant Voltage (Voltage Source)**
If you keep the **voltage constant** while increasing resistance:

- **Current decreases**: According to Ohm’s Law, with constant voltage, an increase in resistance reduces current.
- **Power decreases**: Since power is \( P = \frac{V^2}{R} \), increasing \( R \) with constant \( V \) results in lower power dissipation.
- **Temperature decreases**: Less power dissipation means less heat generated, so the temperature of the resistor or circuit components will decrease.

#### **Scenario 2: Constant Current (Current Source)**
If you keep the **current constant** while increasing resistance:

- **Power increases**: The power dissipation follows the formula \( P = I^2 \times R \). If current remains constant, increasing resistance increases power dissipation.
- **Temperature increases**: More power means more heat generated, so the temperature of the resistor or circuit components will increase.

#### **Scenario 3: Varying Voltage and Current (Complex Circuits)**
In more complex circuits, where both voltage and current vary in response to changes in resistance:

- **The effect on temperature can be mixed**: The changes in power dissipation will depend on how the current and voltage behave in response to the increasing resistance. Generally, an increase in resistance tends to reduce current, but if the current is forced to stay the same, temperature can rise sharply due to the increase in power dissipation.

### Summary:
- **Constant voltage (common scenario)**: Increasing resistance lowers current, reduces power dissipation, and lowers temperature.
- **Constant current**: Increasing resistance raises power dissipation and raises temperature.

The key takeaway is that temperature is directly tied to power dissipation, which is influenced by the resistance, current, and voltage in the circuit.
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