To find the node voltages in a circuit using Kirchhoff’s Current Law (KCL), you follow a systematic approach. Here’s a detailed step-by-step method to help you:
### 1. **Identify the Nodes**
- Determine all the nodes in the circuit.
- Choose one node as the reference node (ground). The voltages at all other nodes will be measured with respect to this reference node.
### 2. **Assign Node Voltages**
- Assign a variable for the voltage at each of the non-reference nodes. For example, if you have nodes \( V_1 \), \( V_2 \), and \( V_3 \), you would denote the voltages at these nodes as \( V_1 \), \( V_2 \), and \( V_3 \) respectively.
### 3. **Write KCL Equations**
- For each node (except the reference node), apply KCL. KCL states that the algebraic sum of currents entering a node is zero. In other words, the sum of all currents flowing into a node is equal to the sum of all currents flowing out of the node.
- Express the currents in terms of node voltages and resistances using Ohm’s Law. The current \( I \) through a resistor \( R \) between two nodes with voltages \( V_a \) and \( V_b \) is \( I = \frac{V_a - V_b}{R} \).
### 4. **Formulate the Equations**
- For each node, write the KCL equation based on the currents flowing into and out of the node.
- For example, if you have a node with resistors connecting it to nodes \( V_a \), \( V_b \), and \( V_c \), the KCL equation at this node can be written as:
\[
\frac{V - V_a}{R_{1}} + \frac{V - V_b}{R_{2}} + \frac{V - V_c}{R_{3}} = 0
\]
where \( V \) is the voltage at the node of interest and \( R_{1} \), \( R_{2} \), and \( R_{3} \) are the resistances connected to other nodes.
### 5. **Solve the System of Equations**
- You will end up with a system of linear equations, one for each non-reference node.
- Solve these simultaneous equations to find the values of the node voltages.
### Example
Let’s solve a simple example:
#### Circuit Description:
- **Node A**: Connected to node B through \( R_1 \) and to node C through \( R_2 \).
- **Node B**: Connected to node A through \( R_1 \) and to ground through \( R_3 \).
- **Node C**: Connected to node A through \( R_2 \) and to ground through \( R_4 \).
#### Steps:
1. **Assign Node Voltages:**
- Let \( V_A \), \( V_B \), and \( V_C \) be the voltages at nodes A, B, and C respectively. Assume the reference node (ground) is at zero volts.
2. **Write KCL Equations:**
- For node A:
\[
\frac{V_A - V_B}{R_1} + \frac{V_A - V_C}{R_2} = 0
\]
- For node B:
\[
\frac{V_B - V_A}{R_1} + \frac{V_B - 0}{R_3} = 0
\]
- For node C:
\[
\frac{V_C - V_A}{R_2} + \frac{V_C - 0}{R_4} = 0
\]
3. **Solve the System:**
- Substitute the resistor values and solve these equations to find \( V_A \), \( V_B \), and \( V_C \).
By following these steps, you can use KCL to find the voltages at different nodes in an electrical circuit.