Finding equivalent resistance in a circuit involves determining a single resistor that could replace a network of resistors while keeping the same overall effect on the circuit. Here’s a step-by-step guide on how to calculate equivalent resistance for different resistor configurations:
### 1. **Series Circuit**
In a series circuit, resistors are connected end-to-end, so the same current flows through each resistor.
**Formula:**
\[ R_{eq} = R_1 + R_2 + R_3 + \ldots + R_n \]
**Example:**
If you have three resistors in series with resistances of \( 4 \, \Omega \), \( 6 \, \Omega \), and \( 10 \, \Omega \):
\[ R_{eq} = 4 \, \Omega + 6 \, \Omega + 10 \, \Omega = 20 \, \Omega \]
### 2. **Parallel Circuit**
In a parallel circuit, resistors are connected across the same two points, so they all have the same voltage across them, and the total current is the sum of the currents through each resistor.
**Formula:**
\[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \ldots + \frac{1}{R_n} \]
**Example:**
If you have three resistors in parallel with resistances of \( 4 \, \Omega \), \( 6 \, \Omega \), and \( 12 \, \Omega \):
\[ \frac{1}{R_{eq}} = \frac{1}{4 \, \Omega} + \frac{1}{6 \, \Omega} + \frac{1}{12 \, \Omega} \]
\[ \frac{1}{R_{eq}} = 0.25 + 0.1667 + 0.0833 \]
\[ \frac{1}{R_{eq}} = 0.5 \]
\[ R_{eq} = 2 \, \Omega \]
### 3. **Series-Parallel Circuits**
For circuits that have both series and parallel components, break down the circuit into simpler series or parallel sections, find the equivalent resistance for each section, and then combine these results step-by-step.
**Steps:**
1. **Identify and Simplify**: Start by identifying resistors that are purely in series or parallel.
2. **Calculate**: Compute the equivalent resistance for these groups.
3. **Redraw**: Simplify the circuit by replacing the simplified groups with their equivalent resistance.
4. **Repeat**: Repeat the process until you reduce the entire circuit to a single equivalent resistance.
**Example:**
Consider a circuit with a \( 10 \, \Omega \) resistor in series with a parallel combination of \( 5 \, \Omega \) and \( 10 \, \Omega \) resistors.
- **Calculate the parallel combination**:
\[ \frac{1}{R_{parallel}} = \frac{1}{5 \, \Omega} + \frac{1}{10 \, \Omega} \]
\[ \frac{1}{R_{parallel}} = 0.2 + 0.1 \]
\[ \frac{1}{R_{parallel}} = 0.3 \]
\[ R_{parallel} = \frac{1}{0.3} = 3.33 \, \Omega \]
- **Add the series resistor**:
\[ R_{eq} = 10 \, \Omega + 3.33 \, \Omega = 13.33 \, \Omega \]
### 4. **Complex Circuits**
For more complex circuits, it may be necessary to use techniques such as:
- **Star-Delta Transformations**: To simplify resistors that are not easily reducible into series or parallel configurations.
- **Mesh or Nodal Analysis**: Advanced techniques involving Kirchhoff’s laws for more complex networks.
### Summary
- **Series Resistors**: Simply add their resistances.
- **Parallel Resistors**: Use the reciprocal sum formula.
- **Complex Networks**: Break down into simpler series/parallel sections and combine results.
Understanding how to break down and simplify circuits step by step will help you find the equivalent resistance accurately.