πŸ”
Why terminal potential difference is less than the emf of a cell?

2 Answers

 
️
Best answer
The terminal potential difference of a cell is often less than its electromotive force (emf) due to internal resistance. When a current flows through the cell, some energy is lost within the cell itself as heat due to this internal resistance. This leads to a drop in potential across the internal resistance, resulting in a lower terminal voltage than the emf.

The relationship can be expressed by the equation:

\[
V = \text{emf} - I \cdot r_{\text{internal}}
\]

where:
- \( V \) is the terminal potential difference,
- \( \text{emf} \) is the electromotive force of the cell,
- \( I \) is the current flowing through the circuit,
- \( r_{\text{internal}} \) is the internal resistance of the cell.

So, when there is current flow, the terminal voltage is reduced because of the voltage drop across the internal resistance.
0 like 0 dislike
The terminal potential difference (V) of a cell is generally less than its electromotive force (EMF, \( \mathcal{E} \)) due to the internal resistance of the cell. To understand this concept thoroughly, let’s break it down step by step:

### 1. **EMF of a Cell**

The EMF of a cell, denoted by \( \mathcal{E} \), is the maximum potential difference between the cell's terminals when no current is flowing (i.e., in an open-circuit condition). It represents the total electrical energy provided per coulomb of charge by the cell.

### 2. **Internal Resistance**

Every real cell or battery has some internal resistance (r), which is the resistance offered by the materials inside the cell to the flow of current. This internal resistance causes a voltage drop inside the cell when current flows.

### 3. **Terminal Potential Difference**

When the cell is connected in a circuit and current (I) flows, the terminal potential difference (V) across the cell is affected by the internal resistance. The relationship between EMF, terminal potential difference, current, and internal resistance can be described by the following equation:

\[ V = \mathcal{E} - I \cdot r \]

where:
- \( V \) is the terminal potential difference,
- \( \mathcal{E} \) is the EMF of the cell,
- \( I \) is the current flowing through the cell,
- \( r \) is the internal resistance of the cell.

### 4. **Why Terminal Potential Difference is Less**

When current flows through the cell, a part of the EMF is used to overcome the internal resistance. This causes a drop in voltage inside the cell. The terminal potential difference you measure is therefore less than the EMF by an amount equal to the voltage drop across the internal resistance, which is \( I \cdot r \).

### 5. **Example to Illustrate**

Consider a cell with an EMF of 12V and an internal resistance of 1 ohm. Suppose a current of 2A is flowing through the cell. The voltage drop due to the internal resistance can be calculated as:

\[ \text{Voltage drop} = I \cdot r = 2 \text{A} \times 1 \text{ohm} = 2 \text{V} \]

So, the terminal potential difference is:

\[ V = \mathcal{E} - I \cdot r = 12 \text{V} - 2 \text{V} = 10 \text{V} \]

Thus, the terminal potential difference (10V) is less than the EMF (12V) by the amount of the internal voltage drop.

### 6. **Conclusion**

The key reason why the terminal potential difference is less than the EMF of a cell is due to the internal resistance that causes a voltage drop when current flows. This difference becomes more pronounced with higher currents and larger internal resistances.
0 like 0 dislike

Related questions

Why the terminal potential difference of a cell is always less than its emf?
Answer : The relationship between the terminal potential difference of a cell (often referred to as the terminal voltage) and its electromotive force (emf) is an important concept in electrical engineering ... as it impacts the efficiency and performance of electrical devices powered by batteries or cells....

Show More

Why terminal potential difference is less than the emf of the cell?
Answer : The terminal potential difference (V) is less than the electromotive force (emf, denoted as \( \mathcal{E} \)) of a cell due to the **internal resistance** of the cell. Here's ... . The more current the cell supplies, the greater the internal resistance losses, reducing the terminal voltage further....

Show More

Why is terminal potential difference always less than emf of the cell?
Answer : The terminal potential difference of a cell is always less than its electromotive force (emf) due to the internal resistance of the cell. When a current flows through the cell, some of the energy ... potential difference is always less than the emf when a current is being drawn from the cell....

Show More

Under what condition is the emf of a cell less than the terminal potential difference?
Answer : The electromotive force (EMF) of a cell is typically greater than or equal to the terminal potential difference (V) under normal conditions, but there is a specific scenario where the EMF could be ... the EMF due to the combination of overcoming the cell's natural EMF and its internal resistance....

Show More

Why terminal potential is less than the emf of a cell?
Answer : The terminal potential of a cell, often referred to as the terminal voltage, is usually less than the electromotive force (EMF) of the cell due to a phenomenon known as voltage drop. ... how batteries perform under load and helps in improving the design and efficiency of energy storage devices....

Show More
Welcome to Electrical Engineering, where you can ask questions and receive answers from other members of the community.