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Is resistance directly proportional to area of cross-section?

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Resistance is not directly proportional to the area of cross-section; in fact, it is inversely proportional. The relationship between resistance (\( R \)), resistivity (\( \rho \)), length (\( L \)), and cross-sectional area (\( A \)) of a conductor is given by the formula:

\[
R = \frac{\rho L}{A}
\]

### Breakdown of the Formula

1. **Resistivity (\( \rho \))**: This is a material-specific property that indicates how strongly a material opposes the flow of electric current. It's measured in ohm-meters (Ω·m).

2. **Length (\( L \))**: This is the length of the conductor. The longer the conductor, the higher the resistance, as electrons encounter more collisions with atoms in the material.

3. **Cross-sectional Area (\( A \))**: This is the area of the conductor's cross-section (e.g., for a circular wire, it would be \(\pi r^2\), where \( r \) is the radius). A larger cross-sectional area allows more electrons to flow through simultaneously, thus reducing resistance.

### Summary of Relationships

- **Inversely Proportional to Area**: As the cross-sectional area increases, the resistance decreases, assuming the length and resistivity remain constant.
  
- **Directly Proportional to Length**: As the length of the conductor increases, the resistance increases.

### Practical Implications

In practical applications, this means that if you want to reduce the resistance in a wire, you can either increase its cross-sectional area (using a thicker wire) or shorten its length. This principle is vital in electrical engineering, particularly in designing circuits and selecting materials for wiring and components.
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No, electrical resistance is not directly proportional to the area of the cross-section. Instead, the relationship between resistance and the cross-sectional area of a conductor is inversely proportional. Here’s a detailed explanation:

### **Resistance and Cross-Sectional Area**

The resistance \( R \) of a conductor is given by the formula:
\[ R = \rho \frac{L}{A} \]

where:
- \( \rho \) (rho) is the resistivity of the material, which is a property of the material and does not change with the dimensions of the conductor.
- \( L \) is the length of the conductor.
- \( A \) is the cross-sectional area of the conductor.

### **Understanding the Formula**

From the formula, we can see that:

- **Resistivity (\( \rho \))**: This is a material property and does not change based on the dimensions of the conductor.
- **Length (\( L \))**: Resistance is directly proportional to the length of the conductor. If the length increases, the resistance increases.
- **Cross-Sectional Area (\( A \))**: Resistance is inversely proportional to the cross-sectional area. If the area increases, the resistance decreases.

### **Why is Resistance Inversely Proportional to the Cross-Sectional Area?**

1. **Electron Flow**: In a conductor, electrical current is carried by electrons. When the cross-sectional area is larger, there is more space for the electrons to flow through. This reduces the likelihood of collisions between electrons and atoms in the conductor, which in turn reduces resistance.
   
2. **Pathway for Current**: A larger cross-sectional area provides a broader pathway for the current to pass through, decreasing the opposition to the flow of electric charge.

### **Practical Example**

Imagine you have a wire made of the same material and of the same length, but you have two wires with different cross-sectional areas. If one wire is thin and the other is thick, the thin wire will have higher resistance compared to the thick wire. This is because the thick wire has a larger cross-sectional area through which the electrons can flow more freely, leading to less resistance.

### **Summary**

In summary, resistance is inversely proportional to the cross-sectional area of a conductor. As the area increases, the resistance decreases, and as the area decreases, the resistance increases, assuming that the length and material of the conductor remain constant.
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