No, the voltage across a capacitor **cannot change abruptly**. This is because of the fundamental relationship between the voltage (\(V\)) across a capacitor, the capacitance (\(C\)), and the charge (\(Q\)) stored on the capacitor's plates, described by the equation:
\[
V = \frac{Q}{C}
\]
### Key reasons why the voltage cannot change suddenly:
1. **Capacitance and Charge Relationship**:
Voltage across a capacitor is directly proportional to the charge on its plates. For the voltage to change abruptly, the charge would also need to change instantaneously. However, it takes time for charge to move onto or off the plates of a capacitor, governed by the current flow into the capacitor. Instantaneous charge movement is not physically possible.
2. **Current-Voltage Relationship**:
The current through a capacitor is related to the rate of change of voltage across it. This relationship is given by:
\[
I = C \frac{dV}{dt}
\]
Here, \(I\) is the current through the capacitor, \(C\) is the capacitance, and \( \frac{dV}{dt} \) is the rate of change of voltage over time.
If the voltage were to change instantaneously (i.e., in zero time), \( \frac{dV}{dt} \) would become infinite, implying that an infinite current would be required. Since real circuits cannot supply infinite current, it's impossible for the voltage across a capacitor to change abruptly.
3. **Physical Limitations**:
Capacitors store energy in the electric field between their plates. A sudden change in voltage would imply an instantaneous change in the energy stored, which would require an infinite amount of power or energy to be transferred in zero time. This is physically impossible because all power sources have finite energy and can only transfer energy at a limited rate.
### Practical Implication:
In practical circuits, whenever there’s a change in voltage (for example, due to switching or changes in circuit conditions), the voltage across the capacitor adjusts smoothly over time. This is often modeled by exponential behavior, especially in simple RC (resistor-capacitor) circuits.
For instance, in an RC charging circuit, if a step voltage is applied, the voltage across the capacitor does not immediately jump to the supply voltage. Instead, it rises gradually following the equation:
\[
V(t) = V_{\text{final}} \left( 1 - e^{-\frac{t}{RC}} \right)
\]
This describes an exponential rise where \(V_{\text{final}}\) is the final voltage, \(t\) is time, \(R\) is the resistance, and \(C\) is the capacitance.
### Conclusion:
The voltage across a capacitor changes gradually, not abruptly, because an infinite current would be required to cause an instantaneous change in voltage, which is not possible in real-world circuits.