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What is the formula for one time constant?

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Best answer
The formula for one time constant (\(\tau\)) in an RC (resistor-capacitor) circuit is given by:

\[
\tau = R \times C
\]

where:
- \(\tau\) is the time constant (in seconds),
- \(R\) is the resistance (in ohms), and
- \(C\) is the capacitance (in farads).

In an RL (resistor-inductor) circuit, the time constant is calculated as:

\[
\tau = \frac{L}{R}
\]

where:
- \(L\) is the inductance (in henries).

The time constant indicates how quickly the circuit responds to changes in voltage or current, with a larger time constant resulting in a slower response.
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The "one time constant" formula is commonly used in the context of electronic circuits and systems, particularly those involving capacitors and resistors. It’s a way to measure the response of an RC (resistor-capacitor) circuit to a change in voltage.

In an RC circuit, the time constant (\(\tau\)) is defined as:

\[ \tau = R \times C \]

where:
- \(R\) is the resistance in ohms (\(\Omega\))
- \(C\) is the capacitance in farads (F)

### Understanding the Time Constant

1. **Response Time**: The time constant \(\tau\) represents the time it takes for the voltage across the capacitor to either charge up to about 63.2% of the final value or discharge to about 36.8% of the initial value, following a step change in voltage.

2. **Charging and Discharging**: When charging, the voltage \(V(t)\) across the capacitor as a function of time \(t\) is given by:

   \[ V(t) = V_{final} \left(1 - e^{-\frac{t}{\tau}}\right) \]

   where \(V_{final}\) is the final voltage the capacitor will reach.

   When discharging, the voltage \(V(t)\) across the capacitor is:

   \[ V(t) = V_{initial} \cdot e^{-\frac{t}{\tau}} \]

   where \(V_{initial}\) is the initial voltage across the capacitor before discharging starts.

3. **Implications**: The time constant gives insight into how quickly the circuit responds to changes. A larger time constant means the circuit responds more slowly, while a smaller time constant indicates a quicker response.

### Practical Example

- **For a Resistor (R) of 1 kΩ (1000 Ω) and a Capacitor (C) of 1 µF (1 × 10^-6 F)**:
  
  \[ \tau = R \times C = 1000 \times 1 \times 10^{-6} = 1 \text{ millisecond} \]

  This means the RC circuit will take approximately 1 millisecond to reach 63.2% of its final voltage when charging or to fall to 36.8% of its initial voltage when discharging.

In summary, the formula \(\tau = R \times C\) provides a measure of how quickly an RC circuit responds to changes in voltage, and it’s a fundamental concept in analyzing and designing electronic circuits.
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