A differential amplifier is designed to amplify the difference between two input signals while rejecting any signals common to both inputs. This ability to reject common-mode signals (i.e., signals that are present on both inputs) is crucial in many applications, such as audio systems, communication devices, and sensor interfaces, where noise or interference may affect both inputs equally.
### Key Concepts: Differential and Common-Mode Signals
- **Differential Signal**: The difference between two input signals, often referred to as \(V_d = V_1 - V_2\), where \(V_1\) and \(V_2\) are the input voltages.
- **Common-Mode Signal**: A signal that is present on both input lines equally. This can be represented as \(V_{cm} = (V_1 + V_2)/2\). It often comes from external noise sources like electromagnetic interference (EMI).
### How the Differential Amplifier Works
A differential amplifier typically has two inputs, and its output is based on the voltage difference between them. Let's break down how it rejects common-mode signals:
1. **Balanced Inputs**: The differential amplifier has two identical inputs, meaning it processes both input signals symmetrically. This balanced design is key to rejecting common-mode signals.
2. **Common-Mode Rejection Ratio (CMRR)**: The ability of a differential amplifier to reject common-mode signals is quantified by the **Common-Mode Rejection Ratio** (CMRR). A higher CMRR indicates better performance in rejecting common-mode signals. CMRR is defined as:
\[
\text{CMRR} = 20 \log_{10} \left( \frac{\text{Differential Gain}}{\text{Common-Mode Gain}} \right)
\]
A good differential amplifier has a very high differential gain and very low common-mode gain, meaning it will significantly amplify the difference between \(V_1\) and \(V_2\) (the differential signal) while almost ignoring any common signal.
3. **Subtraction of Inputs**: A differential amplifier amplifies only the difference between the two inputs:
\[
V_{out} = A_d \times (V_1 - V_2)
\]
Where:
- \(V_{out}\) is the output voltage,
- \(A_d\) is the differential gain,
- \(V_1\) and \(V_2\) are the input voltages.
For common-mode signals, since both \(V_1\) and \(V_2\) are the same (or nearly the same), their difference will be close to zero. Thus, the output due to the common-mode signal is greatly reduced, ideally to zero.
4. **Active Devices (Transistors/Op-Amps)**: In practical circuits, transistors or operational amplifiers (op-amps) are used. These devices have internal mechanisms to suppress common-mode signals. For example:
- **Emitter-Coupled Transistors**: In a differential pair using bipolar junction transistors (BJTs), the common emitter node acts as a reference point. If a common-mode signal appears at both bases (inputs), it affects both transistors equally, resulting in no change in the output current difference.
- **Op-Amp-Based Differential Amplifier**: Operational amplifiers are used with feedback resistors to implement precise differential gain while minimizing the effect of common-mode signals.
### Factors Affecting Common-Mode Rejection
Several factors can influence the effectiveness of a differential amplifier’s common-mode rejection:
- **Mismatch in Components**: In real circuits, slight mismatches in resistors or transistor parameters can reduce the CMRR, making the amplifier more sensitive to common-mode signals.
- **Power Supply Noise**: If the power supply is noisy and the noise is coupled into both inputs, it may appear as a common-mode signal. A differential amplifier with a high CMRR can effectively reject this noise.
- **Frequency Dependence**: CMRR is often frequency-dependent. At low frequencies, the CMRR is typically higher, but at higher frequencies (due to parasitic capacitances and other non-ideal effects), the CMRR may degrade.
### Example of Common-Mode Signal Rejection
Suppose the input signals are:
- \(V_1 = 1 \, \text{V} + 100 \, \text{mV (noise)}\)
- \(V_2 = 0 \, \text{V} + 100 \, \mV (same noise)}\)
Here, the common-mode signal is 100 mV of noise, which is the same on both inputs. The differential amplifier will subtract these two signals:
\[
V_d = (1 + 0.1) \, \text{V} - (0 + 0.1) \, \text{V} = 1 \, \text{V}
\]
The noise (100 mV) cancels out, and the amplifier only amplifies the difference between the signals (1 V), rejecting the common-mode noise.
### Conclusion
A differential amplifier rejects common-mode signals by utilizing its ability to amplify only the difference between two input signals while canceling out signals that are common to both. This rejection is primarily achieved through the balanced circuit design and can be measured by the Common-Mode Rejection Ratio (CMRR). With high CMRR, differential amplifiers can effectively reduce the impact of external noise, making them ideal for precision signal processing applications.