Question

How much ampere is in 1.5 ton AC?

Answer 1

To determine the amperage of a 1.5 ton air conditioner, you can use the formula:

\[ \text{Amperage (A)} = \frac{\text{BTU/hr}}{\text{Voltage (V)} \times \text{Efficiency Factor}} \]

A 1.5 ton AC is approximately 18,000 BTU/hr. At a standard voltage of 230V, the amperage will generally be around 7-8 amps, depending on the efficiency and specific model of the unit. Would you like to delve deeper into how these calculations work?

Answer 2

To determine the current draw of a 1.5-ton air conditioner (AC), you'll need to know the AC’s power consumption and the operating voltage. Here’s a step-by-step process to calculate it:

1. **Determine the Power Consumption**:
   - Air conditioners are typically rated in tons, where 1 ton equals 3.517 kW (kilowatts) of cooling capacity. Thus, a 1.5-ton AC has a cooling capacity of:
     \[
     1.5 \text{ tons} \times 3.517 \text{ kW/ton} = 5.2755 \text{ kW}
     \]

2. **Estimate the Power Factor**:
   - Most air conditioners have a power factor between 0.8 and 1.0. For this calculation, let’s assume a power factor of 0.9.

3. **Calculate the Electrical Power in Watts**:
   - The real power consumption (in watts) can be estimated by dividing the cooling capacity by the power factor:
     \[
     \text{Real Power (Watts)} = \frac{\text{Cooling Capacity (kW)}}{\text{Power Factor}} = \frac{5.2755 \text{ kW}}{0.9} \approx 5.86 \text{ kW} \text{ or } 5860 \text{ W}
     \]

4. **Calculate the Current**:
   - Assuming the AC operates on a standard voltage of 230V (common in many regions), you can use the formula:
     \[
     \text{Current (Amperes)} = \frac{\text{Power (Watts)}}{\text{Voltage (Volts)}} = \frac{5860 \text{ W}}{230 \text{ V}} \approx 25.5 \text{ A}
     \]

So, a 1.5-ton air conditioner typically draws around **25.5 amps** at 230 volts. If the AC operates at a different voltage, such as 110V or 415V, the current draw will change accordingly.