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What is 3 to the 3rd power called?
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The power input to a 500V 50Hz 6Pole 3 phase induction motor running at 975 rpm is 40 kW. The stator losses are 1kW and friction and windage losses are 2kW. Calculate: (i) Slip (ii) Rotor copper loss (iii) Shaft power (iv) Efficiency

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Why is it called 3-dimensional?
Answer : It's called "3-dimensional" because it describes space that has three different measurements, or dimensions: length, width, and height (or depth). Each of these dimensions represents a different direction in space, ... and a height (how tall). When you put all three together, you get a 3D object....

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What is the relation between power in 3 phase delta and star connected system?

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What is the change in resistance if the wire is stretched to 3 times its original length?

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What will happen to the resistance of a wire if its length is multiplied by 3?

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A 3 phase line of 4 km length delivers 4000 kW at a p.f of 0.8 lagging to a load the resistance and reactance per km of each conductor are 0.2 Ω and 0.5 Ω respectively if the voltage at the supply end is maintained at 11 kV. Calculate the received end voltage and efficiency of line.

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Develop an ALP to generate a square wave of 1kHz at port pin P1.3. Draw a flowchart for it.

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A 3 φ I.M. has synchronous speed of 250rpm and 4% slip at full load. The rotor has a resistance of 0.02Ω/ph and stand still reactance of 0.15Ω/ph. Calculate i) The speed at which max torque is developed. ii) The ratio of maximum to F. L. torque. iii) The ratio of maximum to starting torque.

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Derive the torque equation of 3 φ I.M. under running condition.k) Explain production of R.M.F. in 3-phase I.M. when 3 φ supply is fed to it. Draw its phasor diagram.

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Calculate speed of motor when delivery maximum voltage. Also calculate the resistance to be added to achieve 3/4th of maximum torque at time of starting.

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Solve the following using Taylor’s Series Method (up to 3 terms): \[ \frac{dy}{dx} = x^2 + y, \quad y(0) = 1 \] Find \( y(0.2) \).
Answer : #### **Solution:** 1. **Taylor Series Expansion:** The Taylor series expansion of \( y(x) \) around \( x = 0 \) is: \[ y(x) = y(0) + x \frac{dy}{dx} \bigg|_{x=0} + \frac{x^2}{2!} \frac{d^2y}{dx^2} \ ... + 0.004 \] \[ = 1.224 \] **Final Answer: \( y(0.2) \approx 1.224 \)**. ---...

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What is the relationship between true power and apparent power called?

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What is the ratio of electric flux density to electric field strength called?

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What is the rate of change of electric potential with respect to displacement called?

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