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Is ohm a derived unit?
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Yes, **ohm (Ω)** is a derived unit in the International System of Units (SI). It measures **electrical resistance** and is derived from the base units of **length (meter, m)**, **mass (kilogram, kg)**, **time (second, s)**, and **electric current (ampere, A)**.

The ohm is defined based on **Ohm's Law**, which states that:

\[
R = \frac{V}{I}
\]

Where:
- \( R \) is the resistance in ohms,
- \( V \) is the potential difference (voltage) in volts,
- \( I \) is the current in amperes.

From the relationship between these quantities, the unit of ohms can be expressed as:

\[
1 \, \Omega = \frac{1 \, \text{volt}}{1 \, \text{ampere}} = \frac{\text{m}^2 \cdot \text{kg}}{\text{s}^3 \cdot \text{A}^2}
\]

Thus, the ohm is derived from the fundamental SI units of measurement.
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Yes, the ohm is a derived unit of electrical resistance in the International System of Units (SI). It is named after the German physicist Georg Simon Ohm.

To understand why it's a derived unit, let's break it down:

1. **Definition**: The ohm (symbol: Ω) measures electrical resistance. It is defined as the resistance between two points of a conductor when a constant potential difference of one volt (V) applied across the conductor produces a current of one ampere (A).

2. **Formula**: Resistance (R) can be calculated using Ohm's Law:
   
   \[ R = \frac{V}{I} \]
   
   where \( V \) is the voltage in volts and \( I \) is the current in amperes.

3. **Base Units**: In terms of SI base units, the ohm can be expressed as:
   
   \[ \text{Ohm} = \frac{\text{Volt}}{\text{Ampere}} \]
   
   Since the volt is derived from the base units of the SI system as \( \text{Volt} = \text{Joule per Coulomb} = \text{(Kilogram} \cdot \text{meter}^2 \text{per second}^3) / \text{Coulomb} \), and the ampere is a base unit itself, the ohm is a derived unit based on these other units.

So, the ohm is derived from the base SI units of length (meter), mass (kilogram), time (second), and electric current (ampere).
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