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What is the formula for current in a series RL circuit?

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Best answer
In a series RL circuit, which consists of a resistor (R) and an inductor (L) connected in series with a voltage source (V), the behavior of the current is influenced by both the resistance and the inductance. The formula for the current in a series RL circuit can be derived from Kirchhoff's voltage law and the basic principles of circuit theory.

### Key Concepts

1. **Inductance (L)**: This property opposes changes in current. When the circuit is first closed, the inductor resists the initial flow of current, leading to a gradual increase in current rather than an instantaneous jump.

2. **Resistance (R)**: This is the opposition to current flow that causes energy dissipation in the form of heat.

3. **Voltage (V)**: This is the potential difference from the power source driving the current through the circuit.

### Current in the Circuit

When the circuit is first connected to a voltage source, the current does not instantly reach its maximum value but instead increases gradually over time. The current \( I(t) \) at any time \( t \) can be expressed with the following formula:

\[
I(t) = \frac{V}{R} \left( 1 - e^{-\frac{R}{L}t} \right)
\]

#### Explanation of the Formula:

- **\(\frac{V}{R}\)**: This term represents the maximum steady-state current that would flow in the circuit if it were purely resistive (no inductance). It's derived from Ohm's Law, where current \( I \) equals voltage \( V \) divided by resistance \( R \).

- **\(e^{-\frac{R}{L}t}\)**: This is an exponential decay function. The term \( -\frac{R}{L}t \) represents the time-dependent behavior of the current. The exponent indicates how quickly the current rises to its maximum value. The ratio \(\frac{R}{L}\) is known as the time constant (\( \tau \)) of the RL circuit, which determines how fast the current changes. A larger value of \( R \) or a smaller value of \( L \) results in a quicker rise in current.

- **\(1 - e^{-\frac{R}{L}t}\)**: This part of the formula shows that the current starts from zero (at \( t = 0 \)) and asymptotically approaches \(\frac{V}{R}\) as time progresses.

### Time Constant

The time constant \( \tau \) is a crucial aspect of RL circuits and is defined as:

\[
\tau = \frac{L}{R}
\]

This indicates how quickly the circuit responds to changes in voltage. For example, after one time constant (\( \tau \)), the current reaches about 63.2% of its maximum value.

### Summary

In summary, the formula for the current in a series RL circuit captures the gradual buildup of current in response to a voltage source. It accounts for both the resistance and inductance in the circuit, allowing us to predict how the current behaves over time. Understanding this concept is essential for analyzing the dynamics of circuits involving inductors and resistors.
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In a series RL circuit, which consists of a resistor \( R \) and an inductor \( L \) connected in series with an alternating current (AC) source, the formula for the current \( I(t) \) depends on the applied voltage and the impedance of the circuit.

### Impedance of the Series RL Circuit

The total impedance \( Z \) of the series RL circuit is given by:
\[ Z = \sqrt{R^2 + (X_L)^2} \]
where \( X_L \) is the inductive reactance, given by:
\[ X_L = \omega L \]
Here, \( \omega \) is the angular frequency of the AC source, \( \omega = 2\pi f \), and \( L \) is the inductance.

### Current in the Circuit

If the applied voltage is \( V(t) = V_0 \cos(\omega t) \), where \( V_0 \) is the peak voltage, the current \( I(t) \) can be found using Ohm's Law:
\[ I(t) = \frac{V(t)}{Z} \]
Substituting the impedance \( Z \), we get:
\[ I(t) = \frac{V_0 \cos(\omega t)}{\sqrt{R^2 + (X_L)^2}} \]

### Phasor Form

In the phasor domain, the current \( I \) can be expressed as:
\[ I = \frac{V}{Z} \]
where \( V \) is the phasor representation of the voltage. The phase angle \( \phi \) between the voltage and the current is given by:
\[ \tan(\phi) = \frac{X_L}{R} \]
The current phasor \( I \) lags the voltage phasor by this phase angle \( \phi \).

So, the complete expression for the current as a function of time in a series RL circuit with an AC source is:
\[ I(t) = \frac{V_0}{\sqrt{R^2 + (X_L)^2}} \cos(\omega t - \phi) \]
where \( \phi = \arctan\left(\frac{X_L}{R}\right) \).
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