In a series RC (resistor-capacitor) circuit, the time constant is a measure of how quickly the circuit responds to changes in voltage. It is defined as the product of the resistance \( R \) and the capacitance \( C \) in the circuit. The time constant, denoted by \( \tau \) (tau), determines how fast the voltage across the capacitor builds up or decays in response to a step change in voltage.
### Time Constant Formula
The formula for the time constant \( \tau \) in a series RC circuit is:
\[ \tau = R \cdot C \]
where:
- \( R \) is the resistance in ohms (Ω)
- \( C \) is the capacitance in farads (F)
### Behavior of the Time Constant
1. **Charging**: When the circuit is powered, the voltage across the capacitor \( V_C(t) \) as it charges follows the equation:
\[ V_C(t) = V_{max} \left(1 - e^{-\frac{t}{\tau}}\right) \]
where \( V_{max} \) is the final voltage of the power source, and \( t \) is the time elapsed.
2. **Discharging**: When the power source is removed and the capacitor discharges, the voltage \( V_C(t) \) across the capacitor decreases according to:
\[ V_C(t) = V_{initial} \cdot e^{-\frac{t}{\tau}} \]
where \( V_{initial} \) is the initial voltage across the capacitor at the moment discharge begins.
### Multiple Choice Question (MCQ) Example
Here's an example of an MCQ related to the time constant of a series RC circuit:
**Question:** In a series RC circuit with a resistor of 10 kΩ and a capacitor of 2 µF, what is the time constant of the circuit?
a) 20 ms
b) 50 ms
c) 10 ms
d) 5 ms
**Solution:**
To find the time constant \( \tau \), use the formula:
\[ \tau = R \cdot C \]
where:
- \( R = 10 \text{ kΩ} = 10,000 \text{ Ω} \)
- \( C = 2 \text{ µF} = 2 \times 10^{-6} \text{ F} \)
So:
\[ \tau = 10,000 \text{ Ω} \times 2 \times 10^{-6} \text{ F} \]
\[ \tau = 0.02 \text{ seconds} \]
\[ \tau = 20 \text{ ms} \]
**Answer:** a) 20 ms