Question

What is the time constant of a series R-C circuit Mcq?

Answer 1

In a series R-C circuit, the time constant (\(\tau\)) is a measure of how quickly the circuit responds to changes in voltage. It is defined as the time required for the voltage across the capacitor to reach approximately 63.2% of its final value after a step change in voltage.

The time constant is given by the formula:

\[ \tau = R \times C \]

where:
- \( R \) is the resistance in ohms (Ω),
- \( C \) is the capacitance in farads (F).

Here’s a multiple-choice question related to this concept:

**Question:** What is the time constant of a series R-C circuit?

**A)** \( \frac{1}{R \times C} \)

**B)** \( R + C \)

**C)** \( R \times C \)

**D)** \( \frac{R}{C} \)

**Correct Answer:** C) \( R \times C \)

**Explanation:** The time constant \(\tau\) of a series R-C circuit is the product of the resistance \(R\) and the capacitance \(C\). It represents how quickly the capacitor charges or discharges through the resistor.

Answer 2

In a series RC circuit, the time constant (τ) is a measure of how quickly the circuit responds to changes in voltage. It represents the time it takes for the voltage across the capacitor to either charge up to about 63.2% of its final value or discharge to about 36.8% of its initial value.

The time constant of a series RC circuit is given by the formula:

\[ \tau = R \times C \]

where:
- \( R \) is the resistance in ohms (Ω)
- \( C \) is the capacitance in farads (F)

Here's a multiple-choice question (MCQ) format that tests understanding of the time constant of a series RC circuit:

**What is the time constant of a series RC circuit?**

a) \( R \times C \)  
b) \( R + C \)  
c) \( \frac{R}{C} \)  
d) \( \frac{C}{R} \)

**Correct Answer: a) \( R \times C \)**

This formula is derived from the exponential charging and discharging behavior of the capacitor. In practical terms, the time constant provides insight into how quickly the capacitor will charge to approximately 63.2% of its maximum voltage or discharge to about 36.8% of its initial voltage after a change in the circuit's conditions.