1 Answer
The Electromotive Force (EMF) equation of a transformer relates the voltage induced in the primary and secondary windings to the number of turns in the coils and the rate of change of magnetic flux.
The general formula for the EMF equation of a transformer is:
\[
E_1 = 4.44 \, f \, N_1 \, \Phi_{\text{max}}
\]
\[
E_2 = 4.44 \, f \, N_2 \, \Phi_{\text{max}}
\]
Where:
Explanation:
This formula assumes ideal transformer conditions (i.e., no losses, perfect coupling between windings, etc.).
For practical use, you can also use the transformer voltage ratio equation, which is derived from the EMF equation:
\[
\frac{E_1}{E_2} = \frac{N_1}{N_2}
\]
This shows that the voltage ratio is directly proportional to the turns ratio.
The general formula for the EMF equation of a transformer is:
\[
E_1 = 4.44 \, f \, N_1 \, \Phi_{\text{max}}
\]
\[
E_2 = 4.44 \, f \, N_2 \, \Phi_{\text{max}}
\]
Where:
- \( E_1 \) = EMF (or induced voltage) in the primary winding (in volts)
- \( E_2 \) = EMF (or induced voltage) in the secondary winding (in volts)
- \( f \) = frequency of the AC supply (in Hz)
- \( N_1 \) = number of turns in the primary winding
- \( N_2 \) = number of turns in the secondary winding
- \( \Phi_{\text{max}} \) = maximum magnetic flux (in Weber)
Explanation:
- 4.44 comes from the formula for the sinusoidal waveform, accounting for the RMS value of the induced voltage.
- \( N_1 \) and \( N_2 \) are the number of turns on the primary and secondary coils, respectively.
- \( \Phi_{\text{max}} \) is the peak value of the magnetic flux that links both windings.
- \( f \) is the frequency of the AC current.
This formula assumes ideal transformer conditions (i.e., no losses, perfect coupling between windings, etc.).
For practical use, you can also use the transformer voltage ratio equation, which is derived from the EMF equation:
\[
\frac{E_1}{E_2} = \frac{N_1}{N_2}
\]
This shows that the voltage ratio is directly proportional to the turns ratio.