1 Answer
The permittivity of silicon (Si) is approximately 11.7 times the permittivity of free space (ε₀).
In other words, the relative permittivity (also called the dielectric constant) of silicon is about 11.7. The permittivity of free space (ε₀) is around 8.854 x 10⁻¹² F/m (farads per meter), so the permittivity of silicon (εᵣ) can be calculated as:
\[
\epsilon_{\text{Si}} = \epsilon_0 \times \epsilon_r
\]
Where:
Thus, the permittivity of silicon is approximately:
\[
\epsilon_{\text{Si}} = 8.854 \times 10^{-12} \times 11.7 \, \text{F/m}
\]
This gives:
\[
\epsilon_{\text{Si}} \approx 1.036 \times 10^{-10} \, \text{F/m}
\]
So, the permittivity of silicon is around 1.036 x 10⁻¹⁰ F/m.
In other words, the relative permittivity (also called the dielectric constant) of silicon is about 11.7. The permittivity of free space (ε₀) is around 8.854 x 10⁻¹² F/m (farads per meter), so the permittivity of silicon (εᵣ) can be calculated as:
\[
\epsilon_{\text{Si}} = \epsilon_0 \times \epsilon_r
\]
Where:
- \(\epsilon_0 = 8.854 \times 10^{-12} \, \text{F/m}\)
- \(\epsilon_r = 11.7\)
Thus, the permittivity of silicon is approximately:
\[
\epsilon_{\text{Si}} = 8.854 \times 10^{-12} \times 11.7 \, \text{F/m}
\]
This gives:
\[
\epsilon_{\text{Si}} \approx 1.036 \times 10^{-10} \, \text{F/m}
\]
So, the permittivity of silicon is around 1.036 x 10⁻¹⁰ F/m.