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Why is current ahead of voltage in capacitor?
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In a capacitor, the current is ahead of the voltage because of the way capacitors store and release electrical energy. Here's an explanation in simple terms:

1. Capacitor's Function:

A capacitor consists of two conductive plates separated by an insulating material (called the dielectric). When a voltage is applied across the plates, the capacitor stores energy by accumulating positive charge on one plate and negative charge on the other.

2. Current and Voltage Relationship:

The key point is that the current (I) through a capacitor is related to the rate of change of the voltage (V) across it. This relationship is given by the formula:

\[
I = C \frac{dV}{dt}
\]

Where:
    1. \( I \) is the current,
    1. \( C \) is the capacitance of the capacitor (a measure of its ability to store charge),
    1. \( \frac{dV}{dt} \) is the rate of change of voltage with respect to time.

3. Why Current Leads Voltage:

    1. The current flows into the capacitor when the voltage is changing. This means that for the capacitor to build up charge (and hence store voltage), the current must flow first.
    1. In other words, when the voltage is increasing, the current is actively charging the capacitor. If the voltage were constant, no current would flow (since no change in voltage means no charging).
  
Therefore, when you apply a sinusoidal voltage, the current through the capacitor will be at its maximum when the voltage is changing most rapidly (at zero crossing), and it will be zero when the voltage is either at its maximum or minimum (where there is no change). This causes the current to "lead" the voltage by a quarter of a cycle (90 degrees).

In Summary:

The current is ahead of the voltage in a capacitor because the current depends on how fast the voltage is changing. The faster the voltage changes, the more current flows into or out of the capacitor, and this causes the current to reach its peak before the voltage does.
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