To calculate the RMS value, form factor, and peak factor of a periodic voltage, you need to have information about the voltage waveform. Since you mentioned equal time intervals, I'll assume you're referring to a waveform that repeats itself in these intervals. Let's break down each term and how to calculate them:
### Definitions
1. **RMS (Root Mean Square) Value:**
The RMS value of a periodic voltage is a measure of its effective value. It is the square root of the average of the squares of the instantaneous values over one period. For a continuous function \( v(t) \) with period \( T \), the RMS value \( V_{RMS} \) is given by:
\[
V_{RMS} = \sqrt{\frac{1}{T} \int_0^T v^2(t) \, dt}
\]
2. **Form Factor:**
The form factor is the ratio of the RMS value to the average (mean) value of the absolute voltage over one period. For a periodic function \( v(t) \), the form factor \( FF \) is:
\[
FF = \frac{V_{RMS}}{V_{DC}}
\]
where \( V_{DC} \) is the average value of the absolute voltage over one period:
\[
V_{DC} = \frac{1}{T} \int_0^T |v(t)| \, dt
\]
3. **Peak Factor (or Crest Factor):**
The peak factor is the ratio of the peak value (maximum absolute value) of the waveform to its RMS value. For a waveform with peak value \( V_{peak} \):
\[
\text{Peak Factor} = \frac{V_{peak}}{V_{RMS}}
\]
### Example Calculation
Assume we have a periodic waveform with the following characteristics for equal time intervals over one period:
- A simple waveform like a sinusoidal function \( v(t) = V_{peak} \sin(\omega t) \) with period \( T \).
#### 1. RMS Value
For a sinusoidal waveform \( v(t) = V_{peak} \sin(\omega t) \):
\[
V_{RMS} = \frac{V_{peak}}{\sqrt{2}}
\]
This is because the RMS value of a sinusoid is \( \frac{V_{peak}}{\sqrt{2}} \).
#### 2. Form Factor
For a sinusoidal waveform, the average value \( V_{DC} \) is zero because the positive and negative halves of the waveform cancel out. To avoid a division by zero, we often use the average of the absolute value for practical purposes:
\[
V_{DC} = \frac{2}{T} \int_0^{T/2} V_{peak} \sin(\omega t) \, dt = \frac{2 V_{peak}}{\pi}
\]
Therefore, the form factor \( FF \) is:
\[
FF = \frac{V_{RMS}}{V_{DC}} = \frac{\frac{V_{peak}}{\sqrt{2}}}{\frac{2 V_{peak}}{\pi}} = \frac{\pi}{2 \sqrt{2}}
\]
Which approximates to 1.11 for a sinusoidal waveform.
#### 3. Peak Factor
For the same sinusoidal waveform:
\[
\text{Peak Factor} = \frac{V_{peak}}{V_{RMS}} = \frac{V_{peak}}{\frac{V_{peak}}{\sqrt{2}}} = \sqrt{2} \approx 1.414
\]
### Summary
- **RMS Value**: For a sinusoidal waveform, \( V_{RMS} = \frac{V_{peak}}{\sqrt{2}} \).
- **Form Factor**: For a sinusoidal waveform, \( FF = \frac{\pi}{2 \sqrt{2}} \approx 1.11 \).
- **Peak Factor**: For a sinusoidal waveform, \( \text{Peak Factor} = \sqrt{2} \approx 1.414 \).
For other waveforms, the calculations would differ, but the principles remain the same. The RMS value is calculated using the integral of the squared function, the form factor uses the average of the absolute function, and the peak factor is the ratio of the peak value to the RMS value.