πŸ”
An industrial consumer charged with the scheduled tariff of Rs.250 /kVA per month for maximum demand and 150 paisa per unit consumed for load factor of 60% and 80%. Find overall cost per unit at i) unity P.F. ii) 0.9 P.F. consider maximum demand of 50 kVA.

2 Answers

 
️
Best answer
To determine the overall cost per unit for an industrial consumer based on the given data, we need to calculate the cost considering both the maximum demand and the energy consumption. Here's how we can approach the problem step by step.

### Given Data:
1. **Scheduled Tariff for Maximum Demand**: Rs. 250 per KVA per month
2. **Energy Charge**: 150 Paisa per unit (which is Rs. 1.50 per unit)
3. **Maximum Demand**: 50 KVA
4. **Load Factors**: 60% and 80%
5. **Power Factor (P.F.)**: 1.0 (Unity) and 0.9

### Steps to Calculate the Overall Cost Per Unit:

1. **Calculate the Maximum Demand Charge:**
   The maximum demand charge is fixed per KVA per month.

   \[
   \text{Maximum Demand Charge} = 50 \text{ KVA} \times 250 \text{ Rs/KVA} = 12500 \text{ Rs/month}
   \]

2. **Calculate the Energy Consumption:**
   The load factor represents the ratio of the average load to the maximum demand. Thus,

   \[
   \text{Average Load} = \text{Load Factor} \times \text{Maximum Demand}
   \]

   For a Load Factor of 60%:
   \[
   \text{Average Load} = 0.60 \times 50 \text{ KVA} = 30 \text{ KVA}
   \]

   For a Load Factor of 80%:
   \[
   \text{Average Load} = 0.80 \times 50 \text{ KVA} = 40 \text{ KVA}
   \]

3. **Calculate the Energy Consumption in kWh:**
   To find the energy consumption in kWh, we use the average load. Assuming 1 month = 30 days and 24 hours per day:

   \[
   \text{Energy Consumption (kWh)} = \text{Average Load (kW)} \times 24 \text{ hours/day} \times 30 \text{ days}
   \]

   For a Load Factor of 60%:
   \[
   \text{Energy Consumption} = 30 \text{ kW} \times 24 \times 30 = 21600 \text{ kWh}
   \]

   For a Load Factor of 80%:
   \[
   \text{Energy Consumption} = 40 \text{ kW} \times 24 \times 30 = 28800 \text{ kWh}
   \]

4. **Calculate the Total Energy Charges:**
   \[
   \text{Energy Charge} = \text{Energy Consumption} \times 1.50 \text{ Rs/kWh}
   \]

   For a Load Factor of 60%:
   \[
   \text{Energy Charge} = 21600 \text{ kWh} \times 1.50 = 32400 \text{ Rs}
   \]

   For a Load Factor of 80%:
   \[
   \text{Energy Charge} = 28800 \text{ kWh} \times 1.50 = 43200 \text{ Rs}
   \]

5. **Calculate the Total Monthly Cost:**
   \[
   \text{Total Monthly Cost} = \text{Maximum Demand Charge} + \text{Energy Charge}
   \]

   For a Load Factor of 60%:
   \[
   \text{Total Monthly Cost} = 12500 \text{ Rs} + 32400 \text{ Rs} = 44900 \text{ Rs}
   \]

   For a Load Factor of 80%:
   \[
   \text{Total Monthly Cost} = 12500 \text{ Rs} + 43200 \text{ Rs} = 55700 \text{ Rs}
   \]

6. **Calculate the Overall Cost Per Unit:**
   \[
   \text{Overall Cost Per Unit} = \frac{\text{Total Monthly Cost}}{\text{Energy Consumption}}
   \]

   For a Load Factor of 60%:
   \[
   \text{Overall Cost Per Unit} = \frac{44900}{21600} \approx 2.08 \text{ Rs/kWh}
   \]

   For a Load Factor of 80%:
   \[
   \text{Overall Cost Per Unit} = \frac{55700}{28800} \approx 1.93 \text{ Rs/kWh}
   \]

### Considering Power Factor:

The power factor (P.F.) does not affect the energy charge directly in this calculation because the tariff is based on KVA and kWh. However, it is useful to understand the load demand in terms of real power (kW).

1. **At Unity P.F. (1.0):**
   The calculations above assume a unity power factor, so no additional adjustments are needed.

2. **At 0.9 P.F.:**
   For a power factor of 0.9, the demand in kW is:

   \[
   \text{Real Power} = \text{Apparent Power} \times \text{P.F.} = 50 \text{ KVA} \times 0.9 = 45 \text{ kW}
   \]

   The energy consumption calculation remains the same as it’s based on the load factor, not the power factor. Therefore, the overall cost per unit remains as calculated above.

### Summary:
- **Overall Cost Per Unit at 60% Load Factor:**
  - Unity P.F.: Rs. 2.08/kWh
  - 0.9 P.F.: Rs. 2.08/kWh

- **Overall Cost Per Unit at 80% Load Factor:**
  - Unity P.F.: Rs. 1.93/kWh
  - 0.9 P.F.: Rs. 1.93/kWh

The power factor does not alter the overall cost per unit directly in this case.
0 like 0 dislike
To find the overall cost per unit of electricity for the industrial consumer with different power factors, we'll need to calculate the total cost and then divide it by the total energy consumed. Let's break it down step by step.

### Given Data:
- **Scheduled Tariff for Maximum Demand:** Rs. 250/KVA per month
- **Energy Cost Tariff:** 150 Paisa (or Rs. 1.50) per unit (kWh)
- **Load Factor:** 60% and 80%
- **Maximum Demand:** 50 KVA

### i) Unity Power Factor (1.0)

**1. Calculate the Maximum Demand Charge:**
\[ \text{Maximum Demand Charge} = \text{Maximum Demand} \times \text{Scheduled Tariff} \]
\[ \text{Maximum Demand Charge} = 50 \, \text{KVA} \times 250 \, \text{Rs/KVA} = 12500 \, \text{Rs/month} \]

**2. Calculate the Energy Consumed:**

- **Load Factor (LF) = 60%:**
\[ \text{Energy Consumed} = \text{Maximum Demand} \times \text{Number of Hours in a Month} \times \text{Load Factor} \]
Assuming a 30-day month, the number of hours in a month is \( 30 \times 24 = 720 \) hours.
\[ \text{Energy Consumed} = 50 \, \text{KVA} \times 720 \, \text{hours} \times 0.60 = 21600 \, \text{kWh} \]

- **Load Factor (LF) = 80%:**
\[ \text{Energy Consumed} = 50 \, \text{KVA} \times 720 \, \text{hours} \times 0.80 = 28800 \, \text{kWh} \]

**3. Calculate the Total Energy Cost:**
\[ \text{Energy Cost} = \text{Energy Consumed} \times \text{Energy Tariff} \]
\[ \text{Energy Cost} = 21600 \, \text{kWh} \times 1.50 \, \text{Rs/kWh} = 32400 \, \text{Rs} \]
\[ \text{Energy Cost} = 28800 \, \text{kWh} \times 1.50 \, \text{Rs/kWh} = 43200 \, \text{Rs} \]

**4. Calculate the Overall Cost per Unit:**

- **Load Factor 60%:**
\[ \text{Total Cost} = \text{Maximum Demand Charge} + \text{Energy Cost} \]
\[ \text{Total Cost} = 12500 \, \text{Rs} + 32400 \, \text{Rs} = 44900 \, \text{Rs} \]
\[ \text{Overall Cost per Unit} = \frac{44900 \, \text{Rs}}{21600 \, \text{kWh}} \approx 2.08 \, \text{Rs/kWh} \]

- **Load Factor 80%:**
\[ \text{Total Cost} = \text{Maximum Demand Charge} + \text{Energy Cost} \]
\[ \text{Total Cost} = 12500 \, \text{Rs} + 43200 \, \text{Rs} = 55700 \, \text{Rs} \]
\[ \text{Overall Cost per Unit} = \frac{55700 \, \text{Rs}}{28800 \, \text{kWh}} \approx 1.93 \, \text{Rs/kWh} \]

### ii) Power Factor of 0.9

Since the power factor does not directly affect the maximum demand charge but affects the energy consumption indirectly, the overall cost per unit remains the same as for unity power factor. The energy consumed remains the same because load factor and power factor are independent in this calculation.

So, the results are:

- **For Load Factor of 60%:**
  - Unity P.F.: \( \approx 2.08 \, \text{Rs/kWh} \)
  - P.F. of 0.9: \( \approx 2.08 \, \text{Rs/kWh} \)

- **For Load Factor of 80%:**
  - Unity P.F.: \( \approx 1.93 \, \text{Rs/kWh} \)
  - P.F. of 0.9: \( \approx 1.93 \, \text{Rs/kWh} \)
0 like 0 dislike

Related questions

For the tariff of 125/kVA of maximum demand and 3.00 per unit consumed; load factor = 50%, find overall cost/unit at i) unity power factor ii) 0.8 p.f consider maximum demand = 10 kVA.
Answer : To calculate the overall cost per unit (kWh) for the given tariff structure, we need to use the following steps: ### Given Data: - **Tariff for maximum demand**: β‚Ή125 per kVA of maximum demand - **Tariff per unit consumed ... = **β‚Ή3.35** 2. **At power factor 0.8**: Overall cost per unit = **β‚Ή3.43**...

Show More

Define voltage regulation of alternator. A 400V, 10 KVA, 3 phase star connected alternator has resistance per phase of 1.0 ohm. Open circuit voltage per phase of 90V is obtained for field current of 1.0 ... per phase and iv) Regulation while supplying a load current of 15A at 0.8 power factor lag.
Answer : **Voltage Regulation of Alternator:** Voltage regulation of an alternator refers to the change in terminal voltage when the alternator shifts from no-load to full-load conditions while the field current remains constant. It' ... (\( E_{oc} \))**: 90 V 4. **Voltage Regulation**: Approximately 264.9%...

Show More

A 20 pole, 693V, 50 Hz, 3 phase, delta connected synchronous motor is operating at no load with normal excitation. It has armature resistance per phase of zero and synchronous reactance of 10 ohm. If ... iii) armature current /phase, iv) power drawn by the motor and v) power developed by armature.
Answer : To solve the problem, let's break it down step by step: ### Given Data - **Number of poles (P)**: 20 - **Voltage (V)**: 693V (line-to-line) - **Frequency (f)**: 50 Hz - ** ... **Power drawn by the motor**: Approximately 4,188 W - **Power developed by the armature**: Approximately 407.6 W...

Show More

30 number, 100W incandescent lamps are used for exterior lighting and it is being recommended to replace with 25 number 20 W CFL or 15 number 20 W fluorescent Tube light. Determine the payback period for each of ... tube Rs.140/-. Assume cost per unit is Rs 4/- and working hours 10 per day.
Answer : To determine the payback period for each lighting replacement option, we'll follow these steps: 1. **Calculate the total power consumption and cost for each option:** **Incandescent Lamps:** ... period is 20 days. - **Fluorescent Tube Replacement:** Payback period is approximately 19.44 days....

Show More

A 20 KVA, 2200/220V, 50 Hz transformer has O.C/S.C test results as follows: O.C.test : 220V, 4.2 A, 148 W (l. v. side), S.C. test : 86V, 10.5 A, 360 W (h. v. side). Determine the regulation at 0.8 P.F lagging at full load.
Answer : To determine the voltage regulation at 0.8 power factor lagging for the transformer, we first need to calculate the full-load current on the low voltage (LV) side, then find the equivalent reactance and ... the ultimate regulation at 0.8 power factor lagging at full load is approximately **304.8%**....

Show More
Welcome to Electrical Engineering, where you can ask questions and receive answers from other members of the community.