The relationship between electromotive force (emf) and the terminal potential difference (also known as the terminal voltage) of a source is an important concept in understanding how electrical sources work, such as batteries and generators.
### Key Definitions
1. **Electromotive Force (emf):** This is the maximum potential difference between the terminals of a source when no current is flowing. It is essentially the energy provided by the source per unit charge. It is a measure of the source’s ability to drive current through a circuit.
2. **Terminal Potential Difference (Terminal Voltage):** This is the actual potential difference measured across the terminals of the source when current is flowing. It is the voltage that you observe in a circuit.
### Relationship
The relationship between emf and terminal potential difference is influenced by the internal resistance of the source. Here’s how they are related:
1. **Internal Resistance:** All real sources of emf have some internal resistance, denoted as \( r \). This internal resistance causes a drop in the potential difference when current flows through the source.
2. **Circuit Relationship:** When a current \( I \) flows through a source with internal resistance \( r \), the terminal potential difference \( V_{terminal} \) is given by:
\[
V_{terminal} = \text{emf} - I \cdot r
\]
This equation shows that the terminal potential difference is less than the emf by an amount equal to the voltage drop across the internal resistance.
### Explanation
1. **When No Current Flows:** If there is no current flowing through the circuit (i.e., the circuit is open), the terminal potential difference is equal to the emf because no voltage is lost across the internal resistance.
2. **When Current Flows:** As current flows through the circuit, the internal resistance causes a voltage drop. The greater the current, the larger this voltage drop, which results in a lower terminal potential difference compared to the emf.
3. **Practical Example:** Consider a battery with an emf of 12 volts and an internal resistance of 1 ohm. If the battery supplies a current of 2 amps to a circuit, the voltage drop across the internal resistance is:
\[
V_{drop} = I \cdot r = 2 \text{ A} \times 1 \text{ Ω} = 2 \text{ V}
\]
Hence, the terminal potential difference is:
\[
V_{terminal} = \text{emf} - V_{drop} = 12 \text{ V} - 2 \text{ V} = 10 \text{ V}
\]
In summary, the emf represents the maximum potential difference a source can provide, while the terminal potential difference is the actual voltage available to the external circuit, which is reduced by the voltage drop across the internal resistance when current flows.