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What is the relationship between electric force and distance as described by Coulomb's law?
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Coulomb's law describes the relationship between the electric force and the distance between two charged objects. It states that the electric force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's law is written as:

\[
F = k_e \frac{{|q_1 q_2|}}{{r^2}}
\]

Where:
    1. \( F \) is the magnitude of the electric force between the two charges,
    1. \( q_1 \) and \( q_2 \) are the magnitudes of the two charges,
    1. \( r \) is the distance between the centers of the two charges,
    1. \( k_e \) is Coulomb's constant (\( 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)).

The Relationship:

  1. Inversely Proportional to the Square of the Distance:
   - As the distance between the charges increases, the electric force decreases rapidly (in proportion to the square of the distance). This means if you double the distance between the charges, the force will be four times weaker.
   - Similarly, if the distance is halved, the force becomes four times stronger.

  1. Directly Proportional to the Product of the Charges:
   - The force also increases if either of the charges increases. If the charges are larger, the force between them is stronger.

To Summarize:

    1. The electric force decreases as the distance between charges increases.
    1. This decrease follows the inverse square law, meaning if the distance doubles, the force becomes one-quarter of its original value.

This is similar to how gravity works between masses, where the force of attraction between two objects is inversely proportional to the square of the distance between them!
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