Question

Which wavelength is largest de Broglie?

Answer 1

The de Broglie wavelength is given by the formula:

\[
\lambda = \frac{h}{p}
\]

Where:

1. \(\lambda\) is the de Broglie wavelength,
   

1. \(h\) is Planck's constant (\(6.626 \times 10^{-34}\, \text{J}\cdot\text{s}\)),
   

1. \(p\) is the momentum of the particle, which is the product of mass (\(m\)) and velocity (\(v\)).
   

So, the wavelength depends on the momentum of the particle. The larger the momentum, the smaller the de Broglie wavelength.

To have the largest de Broglie wavelength:

1. A particle with smaller momentum will have a larger wavelength.
   

1. A slow-moving or less massive particle will have a larger de Broglie wavelength. For example, an electron moving at a slow speed will have a larger wavelength than a fast-moving, more massive particle like a baseball.
   

So, the largest de Broglie wavelength corresponds to a particle with the smallest momentum (lowest mass and/or velocity).