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Which has the smallest de Broglie wavelength?
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The de Broglie wavelength is given by the formula:

\[
\lambda = \frac{h}{mv}
\]

Where:
    1. \(\lambda\) is the de Broglie wavelength
    1. \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J·s}\))
    1. \(m\) is the mass of the particle
    1. \(v\) is the velocity of the particle

To have the smallest de Broglie wavelength, we need to maximize the mass \(m\) and velocity \(v\) of the particle.

Answer:

The particle with the smallest de Broglie wavelength would generally be one that is:
    1. Heavy (large mass): Larger mass reduces the wavelength.
    1. Fast-moving (high velocity): Higher velocity also reduces the wavelength.

So, among common particles, a fast-moving baseball (relatively large mass and speed) would have a much smaller de Broglie wavelength compared to an electron moving at a slower speed.

In general, macroscopic objects (like a baseball or car) will have extremely small de Broglie wavelengths compared to subatomic particles like electrons or protons.
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