The de Broglie wavelength is given by the formula:
\[
\lambda = \frac{h}{mv}
\]
Where:
- \(\lambda\) is the de Broglie wavelength
- \(h\) is Planck's constant (\(6.626 \times 10^{-34} \, \text{J·s}\))
- \(m\) is the mass of the particle
- \(v\) is the velocity of the particle
To have the smallest de Broglie wavelength, we need to maximize the mass \(m\) and velocity \(v\) of the particle.
Answer:
The particle with the smallest de Broglie wavelength would generally be one that is:
- Heavy (large mass): Larger mass reduces the wavelength.
- Fast-moving (high velocity): Higher velocity also reduces the wavelength.
So, among common particles, a
fast-moving baseball (relatively large mass and speed) would have a much smaller de Broglie wavelength compared to an electron moving at a slower speed.
In general, macroscopic objects (like a baseball or car) will have
extremely small de Broglie wavelengths compared to subatomic particles like electrons or protons.