1 Answer
The unit of the de Broglie wavelength is meters (m).
De Broglie wavelength (\( \lambda \)) is related to the momentum (\( p \)) of a particle by the equation:
\[
\lambda = \frac{h}{p}
\]
Where:
Momentum \( p \) has units of kg·m/s, so when you divide Planck's constant (J·s) by momentum (kg·m/s), the result is a length, measured in meters.
De Broglie wavelength (\( \lambda \)) is related to the momentum (\( p \)) of a particle by the equation:
\[
\lambda = \frac{h}{p}
\]
Where:
- \( \lambda \) is the de Broglie wavelength,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J} \cdot \text{s} \)),
- \( p \) is the momentum of the particle.
Momentum \( p \) has units of kg·m/s, so when you divide Planck's constant (J·s) by momentum (kg·m/s), the result is a length, measured in meters.