Recent questions without an upvoted answer

Explain the uses of safety rubber hand gloves and rubber mats in electrical engineering.
Answer : In electrical engineering, safety is paramount. Two of the most fundamental and critical pieces of Personal Protective Equipment (PPE) are **safety rubber hand gloves** and **insulating rubber ... environment and preventing a worker's body from becoming the path of least resistance for electricity....

Describe with reasons the failure of porcelain insulators.
Answer : ### **Introduction: The Role of Porcelain Insulators** Porcelain insulators are a critical component in electrical power systems. Their primary functions are twofold: 1. **Electrical Insulation: ... , and maintenance strategies (like insulator washing) to ensure the reliability of the power grid....

Explain the use of following tools in carrying out electrical wiring installation: (i) Nose pliers (ii) Test lamps (iii) Crimping tools (iv) Cutter.
Answer : General Introduction In electrical wiring, using the correct tool for the job is not just about efficiency; it is a fundamental requirement for safety and the quality of the finished installation. A poor ... Do not use them to cut steel wire or screws, as this will damage the cutting edges....

Explain the process and need of crimping of cable joints.
Answer : ### Introduction: What is Crimping? At its core, **crimping** is a process used to join a wire (conductor) to a metal terminal or connector (like a lug, spade, or pin). It involves ... is identical and reliable. | A ratcheting tool ensures the same, correct pressure is applied every single time. |...

Given n resistors each of resistance R, how will you combine them to get the (i) maximum (ii) minimum effective resistance? What is the ratio of the maximum to minimum resistance?
Answer : The two fundamental ways to combine resistors are in **series** and in **parallel**. These two configurations yield the maximum and minimum possible resistances, respectively. --- ### (i) Maximum Effective Resistance To obtain the * ... {min} = R/n$ | | **Ratio** | $R_{max} / R_{min}$ | $n^2$ |...

A high tension (HT) supply of, say, 6 kV must have a very large internal resistance. Why?
Answer : The primary reason is **safety and current limiting**. Let's use Ohm's Law ($V = IR$) to understand this. A power supply can be modeled as an ideal voltage source ($V_s$) in series ... HT supply for **power transmission** has a very low internal resistance for **efficiency and power delivery**....

A low voltage supply from which one needs high currents must have very low internal resistance. Why?
Answer : ### The Simple Analogy: A Water Pipe Imagine your power supply is a large water tank (representing the voltage) and you need to get a high flow of water (high current) out of a pipe at ... extremely small, this will generate a massive amount of heat, which can damage or destroy the power supply....

Is ohm’s law universally applicable for all conducting elements? If not, give examples of elements which do not obey Ohm’s law.
Answer : The answer is no, **Ohm's law is not universally applicable for all conducting elements.** Ohm's law is an empirical rule, not a fundamental law of nature. It accurately describes the ... under stable conditions, but it is far from a universal law for all materials that conduct electricity....

A steady current flow in a metallic conductor of non-uniform crosssection. Which of these quantities is constant along the conductor: current, current density, electric field, drift speed?
Answer : Here is a detailed explanation for each quantity: ### 1. Current (I) * **Why it's constant:** The term "steady current" implies that the rate of flow of charge ($I = dQ/dt$) is constant. Due to the ... ($v_d$)** | Not Constant | $v_d = I/(nAe)$. Since A is not constant, $v_d$ is not constant. |...

Six lead-acid type of secondary cells each of emf 2.0 V and internal resistance 0.015 Ohm are joined in series to provide a supply to a resistance of 8.5 Ohm . What is the current drawn from the supply and its terminal voltage?
Answer : ### Given Data: * Number of cells, **n = 6** * EMF of each cell, **E_cell = 2.0 V** * Internal resistance of each cell, **r_cell = 0.015 Ω** * External resistance (load), **R = 8.5 Ω ... The current drawn from the supply is **1.40 A**. * The terminal voltage of the supply is **11.9 V**....